TSTP Solution File: PUZ082^1 by cocATP---0.2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : PUZ082^1 : TPTP v6.1.0. Released v3.6.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n110.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:28:57 EDT 2014

% Result   : Theorem 0.36s
% Output   : Proof 0.36s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----ERROR: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : PUZ082^1 : TPTP v6.1.0. Released v3.6.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n110.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 08:13:26 CDT 2014
% % CPUTime  : 0.36 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0x923ab8>, <kernel.Constant object at 0x9238c0>) of role type named peter
% Using role type
% Declaring peter:fofType
% FOF formula (<kernel.Constant object at 0xb01290>, <kernel.DependentProduct object at 0x923c20>) of role type named says
% Using role type
% Declaring says:(fofType->(Prop->Prop))
% FOF formula ((says peter) (forall (X:Prop), (((says peter) X)->(X->False)))) of role axiom named ax1
% A new axiom: ((says peter) (forall (X:Prop), (((says peter) X)->(X->False))))
% FOF formula ((forall (X:Prop), (((says peter) X)->(X->False)))->False) of role conjecture named thm
% Conjecture to prove = ((forall (X:Prop), (((says peter) X)->(X->False)))->False):Prop
% We need to prove ['((forall (X:Prop), (((says peter) X)->(X->False)))->False)']
% Parameter fofType:Type.
% Parameter peter:fofType.
% Parameter says:(fofType->(Prop->Prop)).
% Axiom ax1:((says peter) (forall (X:Prop), (((says peter) X)->(X->False)))).
% Trying to prove ((forall (X:Prop), (((says peter) X)->(X->False)))->False)
% Found x:(forall (X:Prop), (((says peter) X)->(X->False)))
% Found x as proof of (forall (X:Prop), (((says peter) X)->(X->False)))
% Found (x00 x) as proof of False
% Found ((x0 ax1) x) as proof of False
% Found (((x (forall (X:Prop), (((says peter) X)->(X->False)))) ax1) x) as proof of False
% Found (fun (x:(forall (X:Prop), (((says peter) X)->(X->False))))=> (((x (forall (X:Prop), (((says peter) X)->(X->False)))) ax1) x)) as proof of False
% Found (fun (x:(forall (X:Prop), (((says peter) X)->(X->False))))=> (((x (forall (X:Prop), (((says peter) X)->(X->False)))) ax1) x)) as proof of ((forall (X:Prop), (((says peter) X)->(X->False)))->False)
% Got proof (fun (x:(forall (X:Prop), (((says peter) X)->(X->False))))=> (((x (forall (X:Prop), (((says peter) X)->(X->False)))) ax1) x))
% Time elapsed = 0.041653s
% node=18 cost=240.000000 depth=5
% ::::::::::::::::::::::
% % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% (fun (x:(forall (X:Prop), (((says peter) X)->(X->False))))=> (((x (forall (X:Prop), (((says peter) X)->(X->False)))) ax1) x))
% % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
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